Vista Start Menu Enter Command Quick Open Program

  


We know that in Windows Vista and Windows 7, enter specific commands in the Start menu to search for and open the specified program. For example, type CMD and press Enter to open a command prompt. So, can any third-party software be opened in this way?
There are two ways to do this manually:
1. Simple method
* Create a new shortcut, for example, Rubik's shortcut
* Rename to a simple name, for example, MF
* Cut and paste shortcuts to C:/Windows
2. Complex methods
* WIN+R runs regedit
* Found
HKEY_LOCAL_MACHINE/SOFTWARE/Microsoft/Windows/CurrentVersion/App Paths
* Right-click in the left panel - New - key value and rename it to MF.exe
* Double-click the generated Default key in the right panel, modify the key value:
D:/Apps/TweakCube/TweakCube.exe
* Right-click in the right panel - New - String - Named Path
* Double-click to modify its value to "D:/Apps/TweakCube/”
* Restart takes effect
In fact, the easiest way is to open the Rubik's Cube - System Settings - Run Shortcut Commands
Also, don't say anything more, "advertising", such as boring words, introduce us at the same time each time introducing such skills The software is just to make everyone more familiar with our software and more convenient to use. Moreover, it seems that there is nothing wrong with recommending your own software on your own website.

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